-(3x-4)+7=6(8x-10)-13

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Solution for -(3x-4)+7=6(8x-10)-13 equation: 



-(3x-4)+7=6(8x-10)-13

We move all terms to the left:

-(3x-4)+7-(6(8x-10)-13)=0

We get rid of parentheses

-3x-(6(8x-10)-13)+4+7=0



We calculate terms in parentheses: -(6(8x-10)-13), so:

6(8x-10)-13

We multiply parentheses

48x-60-13

We add all the numbers together, and all the variables

48x-73

Back to the equation:

-(48x-73)



We add all the numbers together, and all the variables

-3x-(48x-73)+11=0

We get rid of parentheses

-3x-48x+73+11=0

We add all the numbers together, and all the variables

-51x+84=0

We move all terms containing x to the left, all other terms to the right

-51x=-84

x=-84/-51

x=1+11/17

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