-(3x-4)-(10x-5)+8=-10(x-1)-(6x+11)+3

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Solution for -(3x-4)-(10x-5)+8=-10(x-1)-(6x+11)+3 equation: 



-(3x-4)-(10x-5)+8=-10(x-1)-(6x+11)+3

We move all terms to the left:

-(3x-4)-(10x-5)+8-(-10(x-1)-(6x+11)+3)=0

We get rid of parentheses

-3x-10x-(-10(x-1)-(6x+11)+3)+4+5+8=0



We calculate terms in parentheses: -(-10(x-1)-(6x+11)+3), so:

-10(x-1)-(6x+11)+3

We multiply parentheses

-10x-(6x+11)+10+3

We get rid of parentheses

-10x-6x-11+10+3

We add all the numbers together, and all the variables

-16x+2

Back to the equation:

-(-16x+2)



We add all the numbers together, and all the variables

-13x-(-16x+2)+17=0

We get rid of parentheses

-13x+16x-2+17=0

We add all the numbers together, and all the variables

3x+15=0

We move all terms containing x to the left, all other terms to the right

3x=-15

x=-15/3

x=-5

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