-(3x-5)+(x-3)=42

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Solution for -(3x-5)+(x-3)=42 equation: 



-(3x-5)+(x-3)=42

We move all terms to the left:

-(3x-5)+(x-3)-(42)=0

We get rid of parentheses

-3x+x+5-3-42=0

We add all the numbers together, and all the variables

-2x-40=0

We move all terms containing x to the left, all other terms to the right

-2x=40

x=40/-2

x=-20

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