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-(3x-5)-(11x-5)+5=11(x-1)-(6x+11)+3
We move all terms to the left:
-(3x-5)-(11x-5)+5-(11(x-1)-(6x+11)+3)=0
We get rid of parentheses
-3x-11x-(11(x-1)-(6x+11)+3)+5+5+5=0
We calculate terms in parentheses: -(11(x-1)-(6x+11)+3), so:We add all the numbers together, and all the variables
11(x-1)-(6x+11)+3
We multiply parentheses
11x-(6x+11)-11+3
We get rid of parentheses
11x-6x-11-11+3
We add all the numbers together, and all the variables
5x-19
Back to the equation:
-(5x-19)
-14x-(5x-19)+15=0
We get rid of parentheses
-14x-5x+19+15=0
We add all the numbers together, and all the variables
-19x+34=0
We move all terms containing x to the left, all other terms to the right
-19x=-34
x=-34/-19
x=1+15/19
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