-(3x-5)-(3x-5)+3=-3(x-1)-(6x+2)+3

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Solution for -(3x-5)-(3x-5)+3=-3(x-1)-(6x+2)+3 equation: 



-(3x-5)-(3x-5)+3=-3(x-1)-(6x+2)+3

We move all terms to the left:

-(3x-5)-(3x-5)+3-(-3(x-1)-(6x+2)+3)=0

We get rid of parentheses

-3x-3x-(-3(x-1)-(6x+2)+3)+5+5+3=0



We calculate terms in parentheses: -(-3(x-1)-(6x+2)+3), so:

-3(x-1)-(6x+2)+3

We multiply parentheses

-3x-(6x+2)+3+3

We get rid of parentheses

-3x-6x-2+3+3

We add all the numbers together, and all the variables

-9x+4

Back to the equation:

-(-9x+4)



We add all the numbers together, and all the variables

-6x-(-9x+4)+13=0

We get rid of parentheses

-6x+9x-4+13=0

We add all the numbers together, and all the variables

3x+9=0

We move all terms containing x to the left, all other terms to the right

3x=-9

x=-9/3

x=-3

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