-(3x-7)+3(-7x-4)=5(-4x+9)-118

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Solution for -(3x-7)+3(-7x-4)=5(-4x+9)-118 equation: 



-(3x-7)+3(-7x-4)=5(-4x+9)-118

We move all terms to the left:

-(3x-7)+3(-7x-4)-(5(-4x+9)-118)=0

We multiply parentheses

-(3x-7)-21x-(5(-4x+9)-118)-12=0

We get rid of parentheses

-3x-21x-(5(-4x+9)-118)+7-12=0



We calculate terms in parentheses: -(5(-4x+9)-118), so:

5(-4x+9)-118

We multiply parentheses

-20x+45-118

We add all the numbers together, and all the variables

-20x-73

Back to the equation:

-(-20x-73)



We add all the numbers together, and all the variables

-24x-(-20x-73)-5=0

We get rid of parentheses

-24x+20x+73-5=0

We add all the numbers together, and all the variables

-4x+68=0

We move all terms containing x to the left, all other terms to the right

-4x=-68

x=-68/-4

x=+17

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