-(3x-7)=3(7-2x)-13

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Solution for -(3x-7)=3(7-2x)-13 equation: 



-(3x-7)=3(7-2x)-13

We move all terms to the left:

-(3x-7)-(3(7-2x)-13)=0

We add all the numbers together, and all the variables

-(3x-7)-(3(-2x+7)-13)=0

We get rid of parentheses

-3x-(3(-2x+7)-13)+7=0



We calculate terms in parentheses: -(3(-2x+7)-13), so:

3(-2x+7)-13

We multiply parentheses

-6x+21-13

We add all the numbers together, and all the variables

-6x+8

Back to the equation:

-(-6x+8)



We get rid of parentheses

-3x+6x-8+7=0

We add all the numbers together, and all the variables

3x-1=0

We move all terms containing x to the left, all other terms to the right

3x=1

x=1/3

x=1/3

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