-(3x-8)=2(x-4)+1

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Solution for -(3x-8)=2(x-4)+1 equation: 



-(3x-8)=2(x-4)+1

We move all terms to the left:

-(3x-8)-(2(x-4)+1)=0

We get rid of parentheses

-3x-(2(x-4)+1)+8=0



We calculate terms in parentheses: -(2(x-4)+1), so:

2(x-4)+1

We multiply parentheses

2x-8+1

We add all the numbers together, and all the variables

2x-7

Back to the equation:

-(2x-7)



We get rid of parentheses

-3x-2x+7+8=0

We add all the numbers together, and all the variables

-5x+15=0

We move all terms containing x to the left, all other terms to the right

-5x=-15

x=-15/-5

x=+3

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