-(3x/2)+4=16

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Solution for -(3x/2)+4=16 equation: 



-(3x/2)+4=16

We move all terms to the left:

-(3x/2)+4-(16)=0

We add all the numbers together, and all the variables

-(+3x/2)+4-16=0

We add all the numbers together, and all the variables

-(+3x/2)-12=0

We get rid of parentheses

-3x/2-12=0

We multiply all the terms by the denominator


-3x-12*2=0

We add all the numbers together, and all the variables

-3x-24=0

We move all terms containing x to the left, all other terms to the right

-3x=24

x=24/-3

x=-8

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