-(3y+1)-(-2y-2)=1

Solution for -(3y+1)-(-2y-2)=1 equation:

Simplifying
-1(3y + 1) + -1(-2y + -2) = 1

Reorder the terms:
-1(1 + 3y) + -1(-2y + -2) = 1
(1 * -1 + 3y * -1) + -1(-2y + -2) = 1
(-1 + -3y) + -1(-2y + -2) = 1

Reorder the terms:
-1 + -3y + -1(-2 + -2y) = 1
-1 + -3y + (-2 * -1 + -2y * -1) = 1
-1 + -3y + (2 + 2y) = 1

Reorder the terms:
-1 + 2 + -3y + 2y = 1

Combine like terms: -1 + 2 = 1
1 + -3y + 2y = 1

Combine like terms: -3y + 2y = -1y
1 + -1y = 1

Add '-1' to each side of the equation.
1 + -1 + -1y = 1 + -1

Combine like terms: 1 + -1 = 0
0 + -1y = 1 + -1
-1y = 1 + -1

Combine like terms: 1 + -1 = 0
-1y = 0

Solving
-1y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '-1'.
y = 0

Simplifying
y = 0