-(3y+1)-(-2y-4)=2

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Solution for -(3y+1)-(-2y-4)=2 equation:


Simplifying
-1(3y + 1) + -1(-2y + -4) = 2

Reorder the terms:
-1(1 + 3y) + -1(-2y + -4) = 2
(1 * -1 + 3y * -1) + -1(-2y + -4) = 2
(-1 + -3y) + -1(-2y + -4) = 2

Reorder the terms:
-1 + -3y + -1(-4 + -2y) = 2
-1 + -3y + (-4 * -1 + -2y * -1) = 2
-1 + -3y + (4 + 2y) = 2

Reorder the terms:
-1 + 4 + -3y + 2y = 2

Combine like terms: -1 + 4 = 3
3 + -3y + 2y = 2

Combine like terms: -3y + 2y = -1y
3 + -1y = 2

Solving
3 + -1y = 2

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1y = 2 + -3

Combine like terms: 3 + -3 = 0
0 + -1y = 2 + -3
-1y = 2 + -3

Combine like terms: 2 + -3 = -1
-1y = -1

Divide each side by '-1'.
y = 1

Simplifying
y = 1

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