-(3y+1)-(-2y-5)=2

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Solution for -(3y+1)-(-2y-5)=2 equation:


Simplifying
-1(3y + 1) + -1(-2y + -5) = 2

Reorder the terms:
-1(1 + 3y) + -1(-2y + -5) = 2
(1 * -1 + 3y * -1) + -1(-2y + -5) = 2
(-1 + -3y) + -1(-2y + -5) = 2

Reorder the terms:
-1 + -3y + -1(-5 + -2y) = 2
-1 + -3y + (-5 * -1 + -2y * -1) = 2
-1 + -3y + (5 + 2y) = 2

Reorder the terms:
-1 + 5 + -3y + 2y = 2

Combine like terms: -1 + 5 = 4
4 + -3y + 2y = 2

Combine like terms: -3y + 2y = -1y
4 + -1y = 2

Solving
4 + -1y = 2

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1y = 2 + -4

Combine like terms: 4 + -4 = 0
0 + -1y = 2 + -4
-1y = 2 + -4

Combine like terms: 2 + -4 = -2
-1y = -2

Divide each side by '-1'.
y = 2

Simplifying
y = 2

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