-(3y+2)-(-2y-5)=3

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Solution for -(3y+2)-(-2y-5)=3 equation:


Simplifying
-1(3y + 2) + -1(-2y + -5) = 3

Reorder the terms:
-1(2 + 3y) + -1(-2y + -5) = 3
(2 * -1 + 3y * -1) + -1(-2y + -5) = 3
(-2 + -3y) + -1(-2y + -5) = 3

Reorder the terms:
-2 + -3y + -1(-5 + -2y) = 3
-2 + -3y + (-5 * -1 + -2y * -1) = 3
-2 + -3y + (5 + 2y) = 3

Reorder the terms:
-2 + 5 + -3y + 2y = 3

Combine like terms: -2 + 5 = 3
3 + -3y + 2y = 3

Combine like terms: -3y + 2y = -1y
3 + -1y = 3

Add '-3' to each side of the equation.
3 + -3 + -1y = 3 + -3

Combine like terms: 3 + -3 = 0
0 + -1y = 3 + -3
-1y = 3 + -3

Combine like terms: 3 + -3 = 0
-1y = 0

Solving
-1y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '-1'.
y = 0

Simplifying
y = 0

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