-(3y+2)-(-2y-8)=2

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Solution for -(3y+2)-(-2y-8)=2 equation:


Simplifying
-1(3y + 2) + -1(-2y + -8) = 2

Reorder the terms:
-1(2 + 3y) + -1(-2y + -8) = 2
(2 * -1 + 3y * -1) + -1(-2y + -8) = 2
(-2 + -3y) + -1(-2y + -8) = 2

Reorder the terms:
-2 + -3y + -1(-8 + -2y) = 2
-2 + -3y + (-8 * -1 + -2y * -1) = 2
-2 + -3y + (8 + 2y) = 2

Reorder the terms:
-2 + 8 + -3y + 2y = 2

Combine like terms: -2 + 8 = 6
6 + -3y + 2y = 2

Combine like terms: -3y + 2y = -1y
6 + -1y = 2

Solving
6 + -1y = 2

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -1y = 2 + -6

Combine like terms: 6 + -6 = 0
0 + -1y = 2 + -6
-1y = 2 + -6

Combine like terms: 2 + -6 = -4
-1y = -4

Divide each side by '-1'.
y = 4

Simplifying
y = 4

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