-(3y+2)-(2y-3)=-3

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Solution for -(3y+2)-(2y-3)=-3 equation:


Simplifying
-1(3y + 2) + -1(2y + -3) = -3

Reorder the terms:
-1(2 + 3y) + -1(2y + -3) = -3
(2 * -1 + 3y * -1) + -1(2y + -3) = -3
(-2 + -3y) + -1(2y + -3) = -3

Reorder the terms:
-2 + -3y + -1(-3 + 2y) = -3
-2 + -3y + (-3 * -1 + 2y * -1) = -3
-2 + -3y + (3 + -2y) = -3

Reorder the terms:
-2 + 3 + -3y + -2y = -3

Combine like terms: -2 + 3 = 1
1 + -3y + -2y = -3

Combine like terms: -3y + -2y = -5y
1 + -5y = -3

Solving
1 + -5y = -3

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -5y = -3 + -1

Combine like terms: 1 + -1 = 0
0 + -5y = -3 + -1
-5y = -3 + -1

Combine like terms: -3 + -1 = -4
-5y = -4

Divide each side by '-5'.
y = 0.8

Simplifying
y = 0.8

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