-(3y+2)-(2y-4)=2

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Solution for -(3y+2)-(2y-4)=2 equation:


Simplifying
-1(3y + 2) + -1(2y + -4) = 2

Reorder the terms:
-1(2 + 3y) + -1(2y + -4) = 2
(2 * -1 + 3y * -1) + -1(2y + -4) = 2
(-2 + -3y) + -1(2y + -4) = 2

Reorder the terms:
-2 + -3y + -1(-4 + 2y) = 2
-2 + -3y + (-4 * -1 + 2y * -1) = 2
-2 + -3y + (4 + -2y) = 2

Reorder the terms:
-2 + 4 + -3y + -2y = 2

Combine like terms: -2 + 4 = 2
2 + -3y + -2y = 2

Combine like terms: -3y + -2y = -5y
2 + -5y = 2

Add '-2' to each side of the equation.
2 + -2 + -5y = 2 + -2

Combine like terms: 2 + -2 = 0
0 + -5y = 2 + -2
-5y = 2 + -2

Combine like terms: 2 + -2 = 0
-5y = 0

Solving
-5y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '-5'.
y = 0

Simplifying
y = 0

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