-(3y+3)-(-2y-6)=2

Solution for -(3y+3)-(-2y-6)=2 equation:

Simplifying
-1(3y + 3) + -1(-2y + -6) = 2

Reorder the terms:
-1(3 + 3y) + -1(-2y + -6) = 2
(3 * -1 + 3y * -1) + -1(-2y + -6) = 2
(-3 + -3y) + -1(-2y + -6) = 2

Reorder the terms:
-3 + -3y + -1(-6 + -2y) = 2
-3 + -3y + (-6 * -1 + -2y * -1) = 2
-3 + -3y + (6 + 2y) = 2

Reorder the terms:
-3 + 6 + -3y + 2y = 2

Combine like terms: -3 + 6 = 3
3 + -3y + 2y = 2

Combine like terms: -3y + 2y = -1y
3 + -1y = 2

Solving
3 + -1y = 2

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1y = 2 + -3

Combine like terms: 3 + -3 = 0
0 + -1y = 2 + -3
-1y = 2 + -3

Combine like terms: 2 + -3 = -1
-1y = -1

Divide each side by '-1'.
y = 1

Simplifying
y = 1