-(3y+4-2c)+13=

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Solution for -(3y+4-2c)+13= equation:


Simplifying
-1(3y + 4 + -2c) + 13 = 0

Reorder the terms:
-1(4 + -2c + 3y) + 13 = 0
(4 * -1 + -2c * -1 + 3y * -1) + 13 = 0
(-4 + 2c + -3y) + 13 = 0

Reorder the terms:
-4 + 13 + 2c + -3y = 0

Combine like terms: -4 + 13 = 9
9 + 2c + -3y = 0

Solving
9 + 2c + -3y = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + 2c + -9 + -3y = 0 + -9

Reorder the terms:
9 + -9 + 2c + -3y = 0 + -9

Combine like terms: 9 + -9 = 0
0 + 2c + -3y = 0 + -9
2c + -3y = 0 + -9

Combine like terms: 0 + -9 = -9
2c + -3y = -9

Add '3y' to each side of the equation.
2c + -3y + 3y = -9 + 3y

Combine like terms: -3y + 3y = 0
2c + 0 = -9 + 3y
2c = -9 + 3y

Divide each side by '2'.
c = -4.5 + 1.5y

Simplifying
c = -4.5 + 1.5y

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