-(3y-2)+7=-(4y+5)

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Solution for -(3y-2)+7=-(4y+5) equation: 



-(3y-2)+7=-(4y+5)

We move all terms to the left:

-(3y-2)+7-(-(4y+5))=0

We get rid of parentheses

-3y-(-(4y+5))+2+7=0



We calculate terms in parentheses: -(-(4y+5)), so:

-(4y+5)

We get rid of parentheses

-4y-5

Back to the equation:

-(-4y-5)



We add all the numbers together, and all the variables

-3y-(-4y-5)+9=0

We get rid of parentheses

-3y+4y+5+9=0

We add all the numbers together, and all the variables

y+14=0

We move all terms containing y to the left, all other terms to the right

y=-14

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