-(3y-2)=y-5-2y

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Solution for -(3y-2)=y-5-2y equation: 



-(3y-2)=y-5-2y

We move all terms to the left:

-(3y-2)-(y-5-2y)=0

We add all the numbers together, and all the variables

-(3y-2)-(-1y-5)=0

We get rid of parentheses

-3y+1y+2+5=0

We add all the numbers together, and all the variables

-2y+7=0

We move all terms containing y to the left, all other terms to the right

-2y=-7

y=-7/-2

y=3+1/2

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