-(3z+4)=6z(3z+2)

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Solution for -(3z+4)=6z(3z+2) equation: 



-(3z+4)=6z(3z+2)

We move all terms to the left:

-(3z+4)-(6z(3z+2))=0

We get rid of parentheses

-3z-(6z(3z+2))-4=0



We calculate terms in parentheses: -(6z(3z+2)), so:

6z(3z+2)

We multiply parentheses

18z^2+12z

Back to the equation:

-(18z^2+12z)



We get rid of parentheses

-18z^2-3z-12z-4=0

We add all the numbers together, and all the variables

-18z^2-15z-4=0

a = -18; b = -15; c = -4;
Δ = b2-4ac
Δ = -152-4·(-18)·(-4)
Δ = -63
Delta is less than zero, so there is no solution for the equation

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