-(3z+4)=6z-5(3z+z)

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Solution for -(3z+4)=6z-5(3z+z) equation: 



-(3z+4)=6z-5(3z+z)

We move all terms to the left:

-(3z+4)-(6z-5(3z+z))=0

We add all the numbers together, and all the variables

-(3z+4)-(6z-5(+4z))=0

We get rid of parentheses

-3z-(6z-5(+4z))-4=0



We calculate terms in parentheses: -(6z-5(+4z)), so:

6z-5(+4z)

We multiply parentheses

6z-20z

We add all the numbers together, and all the variables

-14z

Back to the equation:

-(-14z)



We get rid of parentheses

-3z+14z-4=0

We add all the numbers together, and all the variables

11z-4=0

We move all terms containing z to the left, all other terms to the right

11z=4

z=4/11

z=4/11

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