-(3z+5)=6z-3(3z+2)

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Solution for -(3z+5)=6z-3(3z+2) equation: 



-(3z+5)=6z-3(3z+2)

We move all terms to the left:

-(3z+5)-(6z-3(3z+2))=0

We get rid of parentheses

-3z-(6z-3(3z+2))-5=0



We calculate terms in parentheses: -(6z-3(3z+2)), so:

6z-3(3z+2)

We multiply parentheses

6z-9z-6

We add all the numbers together, and all the variables

-3z-6

Back to the equation:

-(-3z-6)



We get rid of parentheses

-3z+3z+6-5=0

We add all the numbers together, and all the variables

1!=0

There is no solution for this equation

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