-(3z-(13z+1))=1+(9z+4)

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Solution for -(3z-(13z+1))=1+(9z+4) equation:


Simplifying
-1(3z + -1(13z + 1)) = 1 + (9z + 4)

Reorder the terms:
-1(3z + -1(1 + 13z)) = 1 + (9z + 4)
-1(3z + (1 * -1 + 13z * -1)) = 1 + (9z + 4)
-1(3z + (-1 + -13z)) = 1 + (9z + 4)

Reorder the terms:
-1(-1 + 3z + -13z) = 1 + (9z + 4)

Combine like terms: 3z + -13z = -10z
-1(-1 + -10z) = 1 + (9z + 4)
(-1 * -1 + -10z * -1) = 1 + (9z + 4)
(1 + 10z) = 1 + (9z + 4)

Reorder the terms:
1 + 10z = 1 + (4 + 9z)

Remove parenthesis around (4 + 9z)
1 + 10z = 1 + 4 + 9z

Combine like terms: 1 + 4 = 5
1 + 10z = 5 + 9z

Solving
1 + 10z = 5 + 9z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-9z' to each side of the equation.
1 + 10z + -9z = 5 + 9z + -9z

Combine like terms: 10z + -9z = 1z
1 + 1z = 5 + 9z + -9z

Combine like terms: 9z + -9z = 0
1 + 1z = 5 + 0
1 + 1z = 5

Add '-1' to each side of the equation.
1 + -1 + 1z = 5 + -1

Combine like terms: 1 + -1 = 0
0 + 1z = 5 + -1
1z = 5 + -1

Combine like terms: 5 + -1 = 4
1z = 4

Divide each side by '1'.
z = 4

Simplifying
z = 4

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