-(4(x+3)/5)=4x-12

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Solution for -(4(x+3)/5)=4x-12 equation: 



-(4(x+3)/5)=4x-12

We move all terms to the left:

-(4(x+3)/5)-(4x-12)=0

We get rid of parentheses

-(4(x+3)/5)-4x+12=0

We multiply all the terms by the denominator


-(4(x+3)-4x*5)+12*5)=0



We calculate terms in parentheses: -(4(x+3)-4x*5), so:

4(x+3)-4x*5

We multiply parentheses

4x-4x*5+12

Wy multiply elements

4x-20x+12

We add all the numbers together, and all the variables

-16x+12

Back to the equation:

-(-16x+12)



We add all the numbers together, and all the variables

-(-16x+12)=0

We get rid of parentheses

16x-12=0

We move all terms containing x to the left, all other terms to the right

16x=12

x=12/16

x=3/4

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