-(4+m)+2m=-(4+m)+2

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Solution for -(4+m)+2m=-(4+m)+2 equation: 



-(4+m)+2m=-(4+m)+2

We move all terms to the left:

-(4+m)+2m-(-(4+m)+2)=0

We add all the numbers together, and all the variables

-(m+4)+2m-(-(m+4)+2)=0

We add all the numbers together, and all the variables

2m-(m+4)-(-(m+4)+2)=0

We get rid of parentheses

2m-m-(-(m+4)+2)-4=0



We calculate terms in parentheses: -(-(m+4)+2), so:

-(m+4)+2

We get rid of parentheses

-m-4+2

We add all the numbers together, and all the variables

-1m-2

Back to the equation:

-(-1m-2)



We add all the numbers together, and all the variables

m-(-1m-2)-4=0

We get rid of parentheses

m+1m+2-4=0

We add all the numbers together, and all the variables

2m-2=0

We move all terms containing m to the left, all other terms to the right

2m=2

m=2/2

m=1

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