-(4/3)a=12

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Solution for -(4/3)a=12 equation: 



-(4/3)a=12

We move all terms to the left:

-(4/3)a-(12)=0



Domain of the equation: 3)a!=0

a!=0/1

a!=0

a∈R



We add all the numbers together, and all the variables

-(+4/3)a-12=0

We multiply parentheses

-4a^2-12=0

a = -4; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·(-4)·(-12)
Δ = -192
Delta is less than zero, so there is no solution for the equation

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