-(4/3)y-(7/2)=(7/6)y-4

Solution for -(4/3)y-(7/2)=(7/6)y-4 equation:

-(4/3)y-(7/2)=(7/6)y-4

We move all terms to the left:

-(4/3)y-(7/2)-((7/6)y-4)=0


Domain of the equation: 3)y!=0

y!=0/1

y!=0

y∈R



Domain of the equation: 6)y-4)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

-(+4/3)y-((+7/6)y-4)-(+7/2)=0

We multiply parentheses

-4y^2-((+7/6)y-4)-(+7/2)=0

We get rid of parentheses

-4y^2-((+7/6)y-4)-7/2=0

We calculate fractions


-4y^2+()/6y-4)*2)+(-42y)/6y-4)*2)=0

We calculate fractions


-4y^2+(()*6y)/36y^2-42y)*6y)/36y^2+(-4)*2)+(=0

We calculate fractions

We do not support eypression: y^4