-(4/5)g=-12

Solution for -(4/5)g=-12 equation:

-(4/5)g=-12

We move all terms to the left:

-(4/5)g-(-12)=0


Domain of the equation: 5)g!=0

g!=0/1

g!=0

g∈R


We add all the numbers together, and all the variables

-(+4/5)g-(-12)=0

We add all the numbers together, and all the variables

-(+4/5)g+12=0

We multiply parentheses

-4g^2+12=0

a = -4; b = 0; c = +12;
Δ = b2-4ac
Δ = 02-4·(-4)·12
Δ = 192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{192}=\sqrt{64*3}=\sqrt{64}*\sqrt{3}=8\sqrt{3}$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{3}}{2*-4}=\frac{0-8\sqrt{3}}{-8}
=-\frac{8\sqrt{3}}{-8}
=-\frac{\sqrt{3}}{-1}
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{3}}{2*-4}=\frac{0+8\sqrt{3}}{-8}
=\frac{8\sqrt{3}}{-8}
=\frac{\sqrt{3}}{-1}
$