-(4a+3)-2=3-(4a+5)

Solution for -(4a+3)-2=3-(4a+5) equation:

Simplifying
-1(4a + 3) + -2 = 3 + -1(4a + 5)

Reorder the terms:
-1(3 + 4a) + -2 = 3 + -1(4a + 5)
(3 * -1 + 4a * -1) + -2 = 3 + -1(4a + 5)
(-3 + -4a) + -2 = 3 + -1(4a + 5)

Reorder the terms:
-3 + -2 + -4a = 3 + -1(4a + 5)

Combine like terms: -3 + -2 = -5
-5 + -4a = 3 + -1(4a + 5)

Reorder the terms:
-5 + -4a = 3 + -1(5 + 4a)
-5 + -4a = 3 + (5 * -1 + 4a * -1)
-5 + -4a = 3 + (-5 + -4a)

Combine like terms: 3 + -5 = -2
-5 + -4a = -2 + -4a

Add '4a' to each side of the equation.
-5 + -4a + 4a = -2 + -4a + 4a

Combine like terms: -4a + 4a = 0
-5 + 0 = -2 + -4a + 4a
-5 = -2 + -4a + 4a

Combine like terms: -4a + 4a = 0
-5 = -2 + 0
-5 = -2

Solving
-5 = -2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.