-(4a-7)-5a=10/a

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Solution for -(4a-7)-5a=10/a equation: 


D( a )

a = 0

a = 0

a = 0

a in (-oo:0) U (0:+oo)

7-(4*a)-(5*a) = 10/a // - 10/a

7-(4*a)-(5*a)-(10/a) = 0

7-4*a-5*a-10*a^-1 = 0

7*a^0-9*a^1-10*a^-1 = 0

(7*a^1-9*a^2-10*a^0)/(a^1) = 0 // * a^2

a^1*(7*a^1-9*a^2-10*a^0) = 0

a^1

7*a-9*a^2-10 = 0

7*a-9*a^2-10 = 0

DELTA = 7^2-(-10*(-9)*4)

DELTA = -311

DELTA < 0

a in { } 

a belongs to the empty set

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