-(4k-4)=2+2(1-2k)

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Solution for -(4k-4)=2+2(1-2k) equation: 



-(4k-4)=2+2(1-2k)

We move all terms to the left:

-(4k-4)-(2+2(1-2k))=0

We add all the numbers together, and all the variables

-(4k-4)-(2+2(-2k+1))=0

We get rid of parentheses

-4k-(2+2(-2k+1))+4=0



We calculate terms in parentheses: -(2+2(-2k+1)), so:

2+2(-2k+1)

determiningTheFunctionDomain
2(-2k+1)+2

We multiply parentheses

-4k+2+2

We add all the numbers together, and all the variables

-4k+4

Back to the equation:

-(-4k+4)



We get rid of parentheses

-4k+4k-4+4=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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