-(4t-6+5t)+(9-5t+3-2t)=7t-(1-6t)

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Solution for -(4t-6+5t)+(9-5t+3-2t)=7t-(1-6t) equation:



-(4t-6+5t)+(9-5t+3-2t)=7t-(1-6t)
We move all terms to the left:
-(4t-6+5t)+(9-5t+3-2t)-(7t-(1-6t))=0
We add all the numbers together, and all the variables
-(9t-6)+(-7t+12)-(7t-(-6t+1))=0
We get rid of parentheses
-9t-7t-(7t-(-6t+1))+6+12=0
We calculate terms in parentheses: -(7t-(-6t+1)), so:
7t-(-6t+1)
We get rid of parentheses
7t+6t-1
We add all the numbers together, and all the variables
13t-1
Back to the equation:
-(13t-1)
We add all the numbers together, and all the variables
-16t-(13t-1)+18=0
We get rid of parentheses
-16t-13t+1+18=0
We add all the numbers together, and all the variables
-29t+19=0
We move all terms containing t to the left, all other terms to the right
-29t=-19
t=-19/-29
t=19/29

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