-(4v-3)+5(9+4v)=128

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Solution for -(4v-3)+5(9+4v)=128 equation: 



-(4v-3)+5(9+4v)=128

We move all terms to the left:

-(4v-3)+5(9+4v)-(128)=0

We add all the numbers together, and all the variables

-(4v-3)+5(4v+9)-128=0

We multiply parentheses

-(4v-3)+20v+45-128=0

We get rid of parentheses

-4v+20v+3+45-128=0

We add all the numbers together, and all the variables

16v-80=0

We move all terms containing v to the left, all other terms to the right

16v=80

v=80/16

v=5

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