-(4v-6+5v)+(9-5v+3-2v)=7v-(1-6v)

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Solution for -(4v-6+5v)+(9-5v+3-2v)=7v-(1-6v) equation: 



-(4v-6+5v)+(9-5v+3-2v)=7v-(1-6v)

We move all terms to the left:

-(4v-6+5v)+(9-5v+3-2v)-(7v-(1-6v))=0

We add all the numbers together, and all the variables

-(9v-6)+(-7v+12)-(7v-(-6v+1))=0

We get rid of parentheses

-9v-7v-(7v-(-6v+1))+6+12=0



We calculate terms in parentheses: -(7v-(-6v+1)), so:

7v-(-6v+1)

We get rid of parentheses

7v+6v-1

We add all the numbers together, and all the variables

13v-1

Back to the equation:

-(13v-1)



We add all the numbers together, and all the variables

-16v-(13v-1)+18=0

We get rid of parentheses

-16v-13v+1+18=0

We add all the numbers together, and all the variables

-29v+19=0

We move all terms containing v to the left, all other terms to the right

-29v=-19

v=-19/-29

v=19/29

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