-(4x-3)-(7x-7)+2=-7(x-4)-(7x+9)+9

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Solution for -(4x-3)-(7x-7)+2=-7(x-4)-(7x+9)+9 equation:



-(4x-3)-(7x-7)+2=-7(x-4)-(7x+9)+9
We move all terms to the left:
-(4x-3)-(7x-7)+2-(-7(x-4)-(7x+9)+9)=0
We get rid of parentheses
-4x-7x-(-7(x-4)-(7x+9)+9)+3+7+2=0
We calculate terms in parentheses: -(-7(x-4)-(7x+9)+9), so:
-7(x-4)-(7x+9)+9
We multiply parentheses
-7x-(7x+9)+28+9
We get rid of parentheses
-7x-7x-9+28+9
We add all the numbers together, and all the variables
-14x+28
Back to the equation:
-(-14x+28)
We add all the numbers together, and all the variables
-11x-(-14x+28)+12=0
We get rid of parentheses
-11x+14x-28+12=0
We add all the numbers together, and all the variables
3x-16=0
We move all terms containing x to the left, all other terms to the right
3x=16
x=16/3
x=5+1/3

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