-(4x-4)-(2x-2)+4=-7(x-9)-(2x+4)+2

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Solution for -(4x-4)-(2x-2)+4=-7(x-9)-(2x+4)+2 equation: 



-(4x-4)-(2x-2)+4=-7(x-9)-(2x+4)+2

We move all terms to the left:

-(4x-4)-(2x-2)+4-(-7(x-9)-(2x+4)+2)=0

We get rid of parentheses

-4x-2x-(-7(x-9)-(2x+4)+2)+4+2+4=0



We calculate terms in parentheses: -(-7(x-9)-(2x+4)+2), so:

-7(x-9)-(2x+4)+2

We multiply parentheses

-7x-(2x+4)+63+2

We get rid of parentheses

-7x-2x-4+63+2

We add all the numbers together, and all the variables

-9x+61

Back to the equation:

-(-9x+61)



We add all the numbers together, and all the variables

-6x-(-9x+61)+10=0

We get rid of parentheses

-6x+9x-61+10=0

We add all the numbers together, and all the variables

3x-51=0

We move all terms containing x to the left, all other terms to the right

3x=51

x=51/3

x=17

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