-(4y+2)-(-3-5)=2

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Solution for -(4y+2)-(-3-5)=2 equation:


Simplifying
-1(4y + 2) + -1(-3 + -5) = 2

Reorder the terms:
-1(2 + 4y) + -1(-3 + -5) = 2
(2 * -1 + 4y * -1) + -1(-3 + -5) = 2
(-2 + -4y) + -1(-3 + -5) = 2

Combine like terms: -3 + -5 = -8
-2 + -4y + -1(-8) = 2

Multiply -1 * -8
-2 + -4y + 8 = 2

Reorder the terms:
-2 + 8 + -4y = 2

Combine like terms: -2 + 8 = 6
6 + -4y = 2

Solving
6 + -4y = 2

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -4y = 2 + -6

Combine like terms: 6 + -6 = 0
0 + -4y = 2 + -6
-4y = 2 + -6

Combine like terms: 2 + -6 = -4
-4y = -4

Divide each side by '-4'.
y = 1

Simplifying
y = 1

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