-(4y+2)-(-3y-8)=1

Solution for -(4y+2)-(-3y-8)=1 equation:

Simplifying
-1(4y + 2) + -1(-3y + -8) = 1

Reorder the terms:
-1(2 + 4y) + -1(-3y + -8) = 1
(2 * -1 + 4y * -1) + -1(-3y + -8) = 1
(-2 + -4y) + -1(-3y + -8) = 1

Reorder the terms:
-2 + -4y + -1(-8 + -3y) = 1
-2 + -4y + (-8 * -1 + -3y * -1) = 1
-2 + -4y + (8 + 3y) = 1

Reorder the terms:
-2 + 8 + -4y + 3y = 1

Combine like terms: -2 + 8 = 6
6 + -4y + 3y = 1

Combine like terms: -4y + 3y = -1y
6 + -1y = 1

Solving
6 + -1y = 1

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -1y = 1 + -6

Combine like terms: 6 + -6 = 0
0 + -1y = 1 + -6
-1y = 1 + -6

Combine like terms: 1 + -6 = -5
-1y = -5

Divide each side by '-1'.
y = 5

Simplifying
y = 5