-(4y+2)-(3y-5)=3

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Solution for -(4y+2)-(3y-5)=3 equation:


Simplifying
-1(4y + 2) + -1(3y + -5) = 3

Reorder the terms:
-1(2 + 4y) + -1(3y + -5) = 3
(2 * -1 + 4y * -1) + -1(3y + -5) = 3
(-2 + -4y) + -1(3y + -5) = 3

Reorder the terms:
-2 + -4y + -1(-5 + 3y) = 3
-2 + -4y + (-5 * -1 + 3y * -1) = 3
-2 + -4y + (5 + -3y) = 3

Reorder the terms:
-2 + 5 + -4y + -3y = 3

Combine like terms: -2 + 5 = 3
3 + -4y + -3y = 3

Combine like terms: -4y + -3y = -7y
3 + -7y = 3

Add '-3' to each side of the equation.
3 + -3 + -7y = 3 + -3

Combine like terms: 3 + -3 = 0
0 + -7y = 3 + -3
-7y = 3 + -3

Combine like terms: 3 + -3 = 0
-7y = 0

Solving
-7y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '-7'.
y = 0

Simplifying
y = 0

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