-(4y+2)-(3y-8)=3

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Solution for -(4y+2)-(3y-8)=3 equation: 



-(4y+2)-(3y-8)=3

We move all terms to the left:

-(4y+2)-(3y-8)-(3)=0

We get rid of parentheses

-4y-3y-2+8-3=0

We add all the numbers together, and all the variables

-7y+3=0

We move all terms containing y to the left, all other terms to the right

-7y=-3

y=-3/-7

y=3/7

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