-(4y+3)-(-3y-4)=1

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Solution for -(4y+3)-(-3y-4)=1 equation:


Simplifying
-1(4y + 3) + -1(-3y + -4) = 1

Reorder the terms:
-1(3 + 4y) + -1(-3y + -4) = 1
(3 * -1 + 4y * -1) + -1(-3y + -4) = 1
(-3 + -4y) + -1(-3y + -4) = 1

Reorder the terms:
-3 + -4y + -1(-4 + -3y) = 1
-3 + -4y + (-4 * -1 + -3y * -1) = 1
-3 + -4y + (4 + 3y) = 1

Reorder the terms:
-3 + 4 + -4y + 3y = 1

Combine like terms: -3 + 4 = 1
1 + -4y + 3y = 1

Combine like terms: -4y + 3y = -1y
1 + -1y = 1

Add '-1' to each side of the equation.
1 + -1 + -1y = 1 + -1

Combine like terms: 1 + -1 = 0
0 + -1y = 1 + -1
-1y = 1 + -1

Combine like terms: 1 + -1 = 0
-1y = 0

Solving
-1y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '-1'.
y = 0

Simplifying
y = 0

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