-(4y+3)-(-3y-5)=2

Solution for -(4y+3)-(-3y-5)=2 equation:

Simplifying
-1(4y + 3) + -1(-3y + -5) = 2

Reorder the terms:
-1(3 + 4y) + -1(-3y + -5) = 2
(3 * -1 + 4y * -1) + -1(-3y + -5) = 2
(-3 + -4y) + -1(-3y + -5) = 2

Reorder the terms:
-3 + -4y + -1(-5 + -3y) = 2
-3 + -4y + (-5 * -1 + -3y * -1) = 2
-3 + -4y + (5 + 3y) = 2

Reorder the terms:
-3 + 5 + -4y + 3y = 2

Combine like terms: -3 + 5 = 2
2 + -4y + 3y = 2

Combine like terms: -4y + 3y = -1y
2 + -1y = 2

Add '-2' to each side of the equation.
2 + -2 + -1y = 2 + -2

Combine like terms: 2 + -2 = 0
0 + -1y = 2 + -2
-1y = 2 + -2

Combine like terms: 2 + -2 = 0
-1y = 0

Solving
-1y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '-1'.
y = 0

Simplifying
y = 0