-(4y+8)=2y-2(3y+4)

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Solution for -(4y+8)=2y-2(3y+4) equation: 



-(4y+8)=2y-2(3y+4)

We move all terms to the left:

-(4y+8)-(2y-2(3y+4))=0

We get rid of parentheses

-4y-(2y-2(3y+4))-8=0



We calculate terms in parentheses: -(2y-2(3y+4)), so:

2y-2(3y+4)

We multiply parentheses

2y-6y-8

We add all the numbers together, and all the variables

-4y-8

Back to the equation:

-(-4y-8)



We get rid of parentheses

-4y+4y+8-8=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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