-(4z-(10z+1))=1+(5z+2)

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Solution for -(4z-(10z+1))=1+(5z+2) equation:


Simplifying
-1(4z + -1(10z + 1)) = 1 + (5z + 2)

Reorder the terms:
-1(4z + -1(1 + 10z)) = 1 + (5z + 2)
-1(4z + (1 * -1 + 10z * -1)) = 1 + (5z + 2)
-1(4z + (-1 + -10z)) = 1 + (5z + 2)

Reorder the terms:
-1(-1 + 4z + -10z) = 1 + (5z + 2)

Combine like terms: 4z + -10z = -6z
-1(-1 + -6z) = 1 + (5z + 2)
(-1 * -1 + -6z * -1) = 1 + (5z + 2)
(1 + 6z) = 1 + (5z + 2)

Reorder the terms:
1 + 6z = 1 + (2 + 5z)

Remove parenthesis around (2 + 5z)
1 + 6z = 1 + 2 + 5z

Combine like terms: 1 + 2 = 3
1 + 6z = 3 + 5z

Solving
1 + 6z = 3 + 5z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-5z' to each side of the equation.
1 + 6z + -5z = 3 + 5z + -5z

Combine like terms: 6z + -5z = 1z
1 + 1z = 3 + 5z + -5z

Combine like terms: 5z + -5z = 0
1 + 1z = 3 + 0
1 + 1z = 3

Add '-1' to each side of the equation.
1 + -1 + 1z = 3 + -1

Combine like terms: 1 + -1 = 0
0 + 1z = 3 + -1
1z = 3 + -1

Combine like terms: 3 + -1 = 2
1z = 2

Divide each side by '1'.
z = 2

Simplifying
z = 2

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