-(5)/(4u-24)=-(2)/(u-6)

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Solution for -(5)/(4u-24)=-(2)/(u-6) equation: 


D( u )

u-6 = 0

4*u-24 = 0

u-6 = 0

u-6 = 0

u-6 = 0 // + 6

u = 6

4*u-24 = 0

4*u-24 = 0

4*u-24 = 0 // + 24

4*u = 24 // : 4

u = 24/4

u = 6

u in (-oo:6) U (6:+oo)

-(5/(4*u-24)) = -(2/(u-6)) // + 2/(u-6)

2/(u-6)-(5/(4*u-24)) = 0

2/(u-6)-5*(4*u-24)^-1 = 0

2/(u-6)-5/(4*u-24) = 0

(-5*(u-6))/((4*u-24)*(u-6))+(2*(4*u-24))/((4*u-24)*(u-6)) = 0

2*(4*u-24)-5*(u-6) = 0

3*u-18 = 0

(3*u-18)/((4*u-24)*(u-6)) = 0

(3*u-18)/((4*u-24)*(u-6)) = 0 // * (4*u-24)*(u-6)

3*u-18 = 0

3*u-18 = 0 // + 18

3*u = 18 // : 3

u = 18/3

u = 6

u in { 6} 

u belongs to the empty set

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