-(5-y)=-(3y+)

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Solution for -(5-y)=-(3y+) equation:



-(5-y)=-(3y+)
We move all terms to the left:
-(5-y)-(-(3y+))=0
We add all the numbers together, and all the variables
-(-1y+5)-(-(+3y))=0
We get rid of parentheses
1y-(-(+3y))-5=0
We calculate terms in parentheses: -(-(+3y)), so:
-(+3y)
We get rid of parentheses
-3y
Back to the equation:
-(-3y)
We add all the numbers together, and all the variables
y-(-3y)-5=0
We get rid of parentheses
y+3y-5=0
We add all the numbers together, and all the variables
4y-5=0
We move all terms containing y to the left, all other terms to the right
4y=5
y=5/4
y=1+1/4

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