-(5/2v+10)+1=(2/v+5)

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Solution for -(5/2v+10)+1=(2/v+5) equation: 


D( v )

v = 0

v = 0

v = 0

v in (-oo:0) U (0:+oo)

1-((5/2)*v)-10 = 2/v+5 // - 2/v+5

1-((5/2)*v)-(2/v)-10-5 = 0

(-5/2)*v-2*v^-1-10-5+1 = 0

-5/2*v^1-2*v^-1-14*v^0 = 0

(-5/2*v^2-14*v^1-2*v^0)/(v^1) = 0 // * v^2

v^1*(-5/2*v^2-14*v^1-2*v^0) = 0

v^1

(-5/2)*v^2-14*v-2 = 0

(-5/2)*v^2-14*v-2 = 0

DELTA = (-14)^2-(-2*4*(-5/2))

DELTA = 176

DELTA > 0

v = (176^(1/2)+14)/(2*(-5/2)) or v = (14-176^(1/2))/(2*(-5/2))

v = (4*11^(1/2)+14)/(-5) or v = (14-4*11^(1/2))/(-5)

v in { (4*11^(1/2)+14)/(-5), (14-4*11^(1/2))/(-5)} 

v in { (4*11^(1/2)+14)/(-5), (14-4*11^(1/2))/(-5) }

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