-(5/3)v+5/4=-2v-(7/4)

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Solution for -(5/3)v+5/4=-2v-(7/4) equation: 



-(5/3)v+5/4=-2v-(7/4)

We move all terms to the left:

-(5/3)v+5/4-(-2v-(7/4))=0



Domain of the equation: 3)v!=0

v!=0/1

v!=0

v∈R



We add all the numbers together, and all the variables

-(+5/3)v-(-2v-(+7/4))+5/4=0

We multiply parentheses

-5v^2-(-2v-(+7/4))+5/4=0

We calculate fractions


-5v^2=0

a = -5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-5)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$v=\frac{-b}{2a}=\frac{0}{-10}=0$

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