-(5/4w+20)+1=5/w+5

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Solution for -(5/4w+20)+1=5/w+5 equation: 


D( w )

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

1-((5/4)*w)-20 = 5/w+5 // - 5/w+5

1-((5/4)*w)-(5/w)-20-5 = 0

(-5/4)*w-5*w^-1-20-5+1 = 0

-5/4*w^1-5*w^-1-24*w^0 = 0

(-5/4*w^2-24*w^1-5*w^0)/(w^1) = 0 // * w^2

w^1*(-5/4*w^2-24*w^1-5*w^0) = 0

w^1

(-5/4)*w^2-24*w-5 = 0

(-5/4)*w^2-24*w-5 = 0

DELTA = (-24)^2-(-5*4*(-5/4))

DELTA = 551

DELTA > 0

w = (551^(1/2)+24)/(2*(-5/4)) or w = (24-551^(1/2))/(2*(-5/4))

w = -2/5*(551^(1/2)+24) or w = -2/5*(24-551^(1/2))

w in { -2/5*(551^(1/2)+24), -2/5*(24-551^(1/2))} 

w in { -2/5*(551^(1/2)+24), -2/5*(24-551^(1/2)) }

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